document.write( "Question 1093864: On a hike up hill, Ted climbs at 3 miles an hour. Going back down, he runs at 5 miles an hour. If it takes him forty minutes longer to climb up than run down, then what is the length of the hike? \n" ); document.write( "

Algebra.Com's Answer #708480 by josgarithmetic(39621) $\"\"$ $\"About$

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document.write( "           SPEED      TIME      DISTANCE\r\n" );
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document.write( "UP         3          d/3           d\r\n" );
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document.write( "DOWN       5          d/5           d\r\n" );
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document.write( "DIFFERENCE          \r\n" );
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\n" ); document.write( "\n" ); document.write( "Travel Rates Rule, RT=D; for RATE, TIME, DISTANCE\r
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\n" ); document.write( "\n" ); document.write( "Forty minutes longer is $\"2%2F3\"$ of an hour longer. This is the DIFFERENCE between the two time quantities.\r
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\n" ); document.write( "\n" ); document.write( " $\"d%2F3-d%2F5=2%2F3\"$ ------solve for d. \n" ); document.write( "

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