document.write( "Question 97361This question is from textbook Algebra 1
\n" ); document.write( ": 2/5m=3
\n" ); document.write( "4/5=m=6\r
\n" ); document.write( "\n" ); document.write( "what was done to the first equation to get the second one?\r
\n" ); document.write( "\n" ); document.write( "2x=10
\n" ); document.write( "2x+4=14\r
\n" ); document.write( "\n" ); document.write( "what was done to the first equation to get the second one?
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Algebra.Com's Answer #70848 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%282%2F5%29m=3\" \r
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\n" ); document.write( "\n" ); document.write( "===> multiply both sides by 2 to get \"2%2A%282%2F5%29m=2%2A3\"==>\"%284%2F5%29m=6\" \r
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\n" ); document.write( "\n" ); document.write( "\"2x=10\" \r
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\n" ); document.write( "\n" ); document.write( "===> Add 4 to both sides to get \"2x%2B4=10%2B4\"==>\"2x%2B4=14\"
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