document.write( "Question 97176: Doy and his son can do a job in 4 1/2 days. After that they have worked for 3 days, Doy got sick and his son finished the work in 6 more days. How many days are required for each of them to do the work? \n" ); document.write( "
Algebra.Com's Answer #70846 by ankor@dixie-net.com(22740)\"\" \"About 
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Doy and his son can do a job in 4 1/2 days. After that they have worked for 3 days, Doy got sick and his son finished the work in 6 more days. How many days are required for each of them to do the work?\r
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\n" ); document.write( "Let the completed job = 1
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\n" ); document.write( "Let S = sons time alone
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\n" ); document.write( "Let D = Doy's time alone
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\n" ); document.write( "Working together for 3 days they would have completed \"3%2F4.5\" of the job
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\n" ); document.write( "The boy worked alone for 6 days so he completed \"6%2FS\" of the job
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\n" ); document.write( "Find S
\n" ); document.write( "\"3%2F4.5\" + \"6%2FS\" = 1
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\n" ); document.write( "Multiply equation by 4.5S to get rid of the denominators, resulting in:
\n" ); document.write( "3s + 4.5(6) = 4.5s
\n" ); document.write( "3s + 27 = 4.5s
\n" ); document.write( "27 = 4.5s - 3s
\n" ); document.write( "1.5s = 27
\n" ); document.write( "s = 17/1.5
\n" ); document.write( "s = 18 days to complete the job, the son working alone
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\n" ); document.write( "Find the time required by Doy working alone, using the \"working together: equation:
\n" ); document.write( "\"4.5%2FD\" + \"4.5%2F18\" = 1
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\n" ); document.write( "Multiply equation by 18D to get rid of the denominators, results:
\n" ); document.write( "4.5(18) + 4.5D = 18D
\n" ); document.write( "81 + 4.5D = 18D
\n" ); document.write( "81 = 18D - 4.5D
\n" ); document.write( "13.5D = 81
\n" ); document.write( "D = 81/13.5
\n" ); document.write( "D = 6 days to complete the job, Doy working alone
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\n" ); document.write( "Did this make sense to you?\r
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