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document.write( "Comparing with the slope intercept form y=mx+b, the tangent line IP\r\n" );
document.write( "whose equation is y=kx+1 has y-intercept (0,b) = I(0,1), and \r\n" );
document.write( "slope m=k.\r\n" );
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document.write( "Since the line goes through I(0,1) and P(3,6), we use the\r\n" );
document.write( "slope formula to determine m = k, its slope:\r\n" );
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<-- that's the answer for k\r\n" );
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document.write( "The radius OP is perpendicular to line IP, so its slope is\r\n" );
document.write( "the reciprocal of
with the opposite sign, so the\r\n" );
document.write( "slope of the radius OP is
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document.write( "To find the equation of OP, we use the point-slope form of \r\n" );
document.write( "a line with
and the point of tangency, P(3,6).\r\n" );
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<--equation of radius OP\r\n" );
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document.write( "Since center O(1,h) is on that radius, we substitute the\r\n" );
document.write( "point (1,h), to find h\r\n" );
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<---that's the answer for h\r\n" );
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document.write( "Edwin
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