document.write( "Question 1093751: On Monday, Harold picked up six donuts and three large coffees for the office staff. He paid $6.39. On Tuesday, Melinda picked up four donuts and six large coffees for the office staff. She paid $7.50. What is the cost of one donut? What is the cost of one large coffee? \n" ); document.write( "
Algebra.Com's Answer #708358 by addingup(3677)![]() ![]() You can put this solution on YOUR website! 6d + 3c = 6.39 multiply all times 2 and subtract from the next equation \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ \n" ); document.write( "12d + 6c = 12.78 \n" ); document.write( "- \n" ); document.write( "4d + 6c = 7.50 \n" ); document.write( "----------------- \n" ); document.write( "8d + 0c = 5.28 \n" ); document.write( "8d = 5.28 \n" ); document.write( "d = 0.66 \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~ \n" ); document.write( "6d + 3c = 6.39 \n" ); document.write( "6(0.66) + 3c = 6.39 \n" ); document.write( "3.96 + 3c = 6.39 \n" ); document.write( "3c = 2.43 \n" ); document.write( "c = 0.81 \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ \n" ); document.write( "Note: I used the first equation to solve for c, but you can use either one of the equations. Here's using the 2nd equation: \n" ); document.write( "4d + 6c = 7.50 \n" ); document.write( "4(0.66) + 6c = 7.50 \n" ); document.write( "2.64 + 6c = 7.50 \n" ); document.write( "6c = 4.86 \n" ); document.write( "c = 0.81\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |