document.write( "Question 1093671: Using the basic identities, find the value of cscΘ if cotΘ = -12/5.
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Algebra.Com's Answer #708323 by Theo(13342)\"\" \"About 
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the triangle formed is a right triangle in the second quadrant.\r
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\n" ); document.write( "\n" ); document.write( "the hypotenuse of that triangle is equal to the square root of the sum of the legs squared which is equal to sqrt(12^2 + 5^2) = sqrt(169) = 13.\r
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\n" ); document.write( "\n" ); document.write( "see the diagram below:\r
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\n" ); document.write( "\n" ); document.write( "in this triangle:\r
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\n" ); document.write( "\n" ); document.write( "opposite side of the angle is equal to 5.
\n" ); document.write( "adjacent side of the angle is equal to -12.
\n" ); document.write( "hypotenuse of the triangle formed is equal to 13.\r
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\n" ); document.write( "\n" ); document.write( "i called the angle T which stands for theta in this case.\r
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\n" ); document.write( "\n" ); document.write( "sin(T) = opposite / hypotenuse = 5/13.\r
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\n" ); document.write( "\n" ); document.write( "csc(T) = hypotenuse / opposite = 13/5\r
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\n" ); document.write( "\n" ); document.write( "csc(T) is also equal to 1 / sin(t) = 1 / (5/13) = 13/5.\r
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\n" ); document.write( "\n" ); document.write( "that's your answer.\r
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\n" ); document.write( "\n" ); document.write( "csc(T) = 13/5\r
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\n" ); document.write( "\n" ); document.write( "general formula used to find the hypotenuse:\r
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\n" ); document.write( "\n" ); document.write( "c^2 = a^2 + b^2\r
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\n" ); document.write( "\n" ); document.write( "c is the hypotenuse
\n" ); document.write( "a is one of the legs of the right triangle.
\n" ); document.write( "b is the other leg of the right triangle.\r
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\n" ); document.write( "\n" ); document.write( "length of the hypotenuse is found by finding sqrt(c^2).\r
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\n" ); document.write( "\n" ); document.write( "when graphing the angle and the right triangle formed:\r
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\n" ); document.write( "\n" ); document.write( "x = a
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\n" ); document.write( "h = c\r
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\n" ); document.write( "\n" ); document.write( "formula becomes h^2 = x^2 + y^2\r
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\n" ); document.write( "\n" ); document.write( "x is the side adjacent to the angle formed.
\n" ); document.write( "y is the side opposite to the angle formed.
\n" ); document.write( "h is the hypotenuse of the right triangle formed.
\n" ); document.write( "the angle formed is at the origin of the graph which is the intersection of the x and y axes.\r
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