document.write( "Question 1093652: sally has only dimes and quarters in her pocket. she has 21 coins all together with a total value of $4.35. how many of each coin type does she have? \n" ); document.write( "
Algebra.Com's Answer #708296 by addingup(3677)![]() ![]() You can put this solution on YOUR website! d + q = 21 subtract quarters from both sides: \n" ); document.write( "d = 21 - q \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ \n" ); document.write( "0.10d + 0.25q = 4.35 substitute for d: \n" ); document.write( "0.10(21 - q) + 0.25q = 4.35 \n" ); document.write( "2.1 - 0.10q + 0.25q = 4.35 \n" ); document.write( "0.15q = 2.25 \n" ); document.write( "q = 2.25/0.15 \n" ); document.write( "q = 15 She has 15 quarters and \n" ); document.write( "21-15 = 6 dimes \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ \n" ); document.write( "Check \n" ); document.write( "0.10(6) = 0.60 \n" ); document.write( "0.25(15) = 3.75 \n" ); document.write( "0.60 + 3.75 = 4.35 correct \n" ); document.write( " \n" ); document.write( " |