document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1093631>Question 1093631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an equation of the line that satisfies the given conditions.<BR>\n" );
document.write( "Through (1/2, -2/5) perpendicular to the line 3x &#8722; 6y = 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #708261 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=708261\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find an equation of the line that satisfies the given conditions.<BR>\n" );
document.write( "Through (1/2, -2/5) perpendicular to the line 3x &#8722; 6y = 1 <BR>\n" );
document.write( "------<BR>\n" );
document.write( "Find slope of given equation::<BR>\n" );
document.write( "6y = 3x-1<BR>\n" );
document.write( "y = (1/2)x-(1/6)<BR>\n" );
document.write( "slope = 1/2<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Then slope of perpendicular line is -2<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Form of answer:: y = mx + b<BR>\n" );
document.write( "Substitute for x, y, and m; Solve for \"b\"\"<BR>\n" );
document.write( "-2/5 = -2(1/2) + b<BR>\n" );
document.write( "b = -2/5 +1<BR>\n" );
document.write( "b = 3/5<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Ans:: y = -2x + 3/5<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "----------------- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );