document.write( "Question 1093627: Father is five less than four times his son's age.
\n" ); document.write( "Eight years from now, the father will be three more than twice his son's age.
\n" ); document.write( "How old are they now? \n" ); document.write( "
Algebra.Com's Answer #708258 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
f=4s-5
\n" ); document.write( "f+8=2(s+8)+3
\n" ); document.write( "4s-5+8=2(s+8)+3
\n" ); document.write( "4s+3=2s+16+3
\n" ); document.write( "2s=16
\n" ); document.write( "s=8
\n" ); document.write( "f=4s-5
\n" ); document.write( "f=27
\n" ); document.write( "check
\n" ); document.write( "f+8=2(s+8)+3
\n" ); document.write( "27+8=2*(16)+3
\n" ); document.write( "35=35
\n" ); document.write( "ok\r
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