document.write( "Question 1093511: A smoke detector system uses two devices A and B. If smoke is present the
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document.write( "probability that it will be detected by device A is 0.95, by device B 0.9 and by
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document.write( "both devices 0.88. \r
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document.write( "a) suppose, before checking the devices, there is a 15% chance of smoke. calculate the probability
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document.write( " that there is smoke given that B didn't detect smoke\r
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document.write( "b) repeat part a), now given that neither A or B detected smoke \n" );
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Algebra.Com's Answer #708254 by ciaV(1) ![]() You can put this solution on YOUR website! a) .1(.15) = .015\r \n" ); document.write( "\n" ); document.write( ".1 = the percentage that B does not detect so that times the the percentage that there is smoke\r \n" ); document.write( "\n" ); document.write( "b) .1(.05)(.15) =7.5 x 10^-4 \n" ); document.write( ".1 = B does not detect \n" ); document.write( ".05= A does not detect \n" ); document.write( " times the percentage that there is smoke \n" ); document.write( " |