document.write( "Question 1093598: $9500 is invested,part of it at 11% and part of it at 9%. For a certain year, the total yield is $973. How much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #708225 by Boreal(15235)\"\" \"About 
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x invested at 11%=0.11x interest
\n" ); document.write( "9500-x invested at 9%=855-.09x interest
\n" ); document.write( "that sum is $973
\n" ); document.write( "0.02x+855=973
\n" ); document.write( "0.02x=118
\n" ); document.write( "multiply by 50,
\n" ); document.write( "x=$5900 @ 11%=$649
\n" ); document.write( "9500-x=$3600@9%=$324
\n" ); document.write( "sum is $973.
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