document.write( "Question 1093598: $9500 is invested,part of it at 11% and part of it at 9%. For a certain year, the total yield is $973. How much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #708225 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x invested at 11%=0.11x interest \n" ); document.write( "9500-x invested at 9%=855-.09x interest \n" ); document.write( "that sum is $973 \n" ); document.write( "0.02x+855=973 \n" ); document.write( "0.02x=118 \n" ); document.write( "multiply by 50, \n" ); document.write( "x=$5900 @ 11%=$649 \n" ); document.write( "9500-x=$3600@9%=$324 \n" ); document.write( "sum is $973. \n" ); document.write( " |