document.write( "Question 97317: can you please help me solve the problems thanks 1. 90 miles over 1 hr equals feet over seconds \r
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document.write( "2. 3.5 cm over 1 second equals meters over 1 min \r
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document.write( "3. 114 over 1 yr equals liters over 1 day \r
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document.write( "4. 500 dallors over 8 hrs equal cents over 1 day \n" );
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Algebra.Com's Answer #70819 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1. 90 miles over 1 hr equals feet over seconds \n" ); document.write( "(90 mi/1 hr) \n" ); document.write( "= (90*5280 ft/3600 sec) \n" ); document.write( "= (475200/3600) ft/sec \n" ); document.write( "= 132 ft/sec \n" ); document.write( "---------------- \n" ); document.write( "2. 3.5 cm over 1 second equals meters over 1 min \n" ); document.write( "(3.5 cm/1 second)(60 seconds/1 min)(1 meter/100 cm) \n" ); document.write( "= (3.5*60*10/(1*1*100)(meters/minute) \n" ); document.write( "= 21 (meters/ minute) \n" ); document.write( "-----------------\r \n" ); document.write( "\n" ); document.write( "3. 114??? over 1 yr equals liters over 1 day \n" ); document.write( "------------------- \n" ); document.write( "4. 500 dollars over 8 hrs equal cents over 1 day \n" ); document.write( "(500 dollars/8 hrs) \n" ); document.write( "= (500*100 cents/(8/24) day)\r \n" ); document.write( "\n" ); document.write( "= (50000/(1/3)) cents/day\r \n" ); document.write( "\n" ); document.write( "= 150000 (cents/day) \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |