document.write( "Question 1093482: could you please help me solve this equation in interval notation \r
\n" ); document.write( "\n" ); document.write( "x-1 > (or equal) 6/x
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Algebra.Com's Answer #708115 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"x-1%3E=6%2Fx\"\r
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\n" ); document.write( "\n" ); document.write( "\"x-1-6%2Fx%3E=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2Fx%29-1%28x%2Fx%29-6%2Fx%3E=0%2A%28x%2Fx%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-x-6%29%2Fx%3E=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28x%2B2%29%28x-3%29%29%2Fx%3E=6\"
\n" ); document.write( "The critical x values to check are -2, 0, 3.
\n" ); document.write( "The INTERVALS to check are for \"system%28-infinity%3Cx%3C=-2%2C-2%3C=x%3C0%2C0%3C=x%3C=3%2C3%3Cx%3Cinfinity%29\".\r
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\n" ); document.write( "\n" ); document.write( "That was \"help\" but not the finished solution. You check each interval to see which satisfy the original inequality and which do not.
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