document.write( "Question 1093436: James invested some money at 5% interest. James also invested $⁢221 more than 2 times that amount at 7%. How much is invested at each rate if James receives $850.52 in interest after one year? (Round to two decimal places if necessary.)\r
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Algebra.Com's Answer #708099 by addingup(3677)\"\" \"About 
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Let some money be x.
\n" ); document.write( "1) So the amount invested at 5% will be 0.05x.
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\n" ); document.write( "2) He invested the rest of the money at 7%. And the problem says this amount is 221 more than 2 times x: 0.07(2x+221)
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\n" ); document.write( "Put these two together:
\n" ); document.write( "0.05x + 0.07(2x+221) = 850.52
\n" ); document.write( "0.05x + 0.07(2x + 221) = 850.52
\n" ); document.write( "0.05x + 0.14x + 15.47 = 850.52
\n" ); document.write( "0.19x = 835.05
\n" ); document.write( "x = 4395 This is the amount invested at 5%
\n" ); document.write( "At 7%: (2*4395)+221 = 9011
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\n" ); document.write( "Let's check to see if I got you the right answer:
\n" ); document.write( "(0.05(4395)) + (0.07(9011)) = 850.52 Correct
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