document.write( "Question 1093430: Two cyclists leave towns
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document.write( "132mi
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document.write( " apart at the same time and travel toward each other. One cyclist travels
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document.write( "4
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document.write( "/mih
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document.write( " faster than the other. If they meet in
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document.write( "3
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document.write( " hours, what is the rate of each cyclist?
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document.write( "
Algebra.Com's Answer #708062 by Alan3354(69443) You can put this solution on YOUR website! Two cyclists leave towns 132mi apart at the same time and travel toward each other. One cyclist travels 4 /mih [sic] **** It's mi/hr *** faster than the other. If they meet in 3 hours, what is the rate of each cyclist? \n" ); document.write( "-------------- \n" ); document.write( "Speeds in opposite directions are added. \n" ); document.write( "------- \n" ); document.write( "Step 1, find the sum of the speeds. \n" ); document.write( "-- \n" ); document.write( "The difference is given, = 4 mi/hr. \n" ); document.write( "----------- \n" ); document.write( "Call the speeds x & y \n" ); document.write( "-- \n" ); document.write( "x + y = sum \n" ); document.write( "x - y = 4 \n" ); document.write( "---------------------- Add \n" ); document.write( "2x = sum + 4 \n" ); document.write( "etc. \n" ); document.write( " |