document.write( "Question 1093430: Two cyclists leave towns
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document.write( "132mi
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document.write( " apart at the same time and travel toward each other. One cyclist travels
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document.write( "4
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document.write( "/mih
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document.write( " faster than the other. If they meet in
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document.write( "3
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document.write( " hours, what is the rate of each cyclist?
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Algebra.Com's Answer #708061 by rothauserc(4718) You can put this solution on YOUR website! let x be the slower cyclist, then \n" ); document.write( ": \n" ); document.write( "3x + (x+4)3 = 132 \n" ); document.write( ": \n" ); document.write( "3x +3x +12 = 132 \n" ); document.write( ": \n" ); document.write( "6x = 120 \n" ); document.write( ": \n" ); document.write( "x = 20 \n" ); document.write( ": \n" ); document.write( "******************************** \n" ); document.write( "rate of slower cyclist is 20 mph \n" ); document.write( "rate of faster cyclist is 24 mph \n" ); document.write( "******************************** \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |