document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=97297>Question 97297</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The number of green beads varied inversely as the square of the number of yellow beads. When there were 8 green, there were 5 yellows. How many would there be if threre were 10 yellows?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #70805 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=70805\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The number of green beads varied inversely as the square of the number of yellow beads.<BR>\n" );
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document.write( "green = k/(yellow)^2<BR>\n" );
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document.write( "When there were 8 green, there were 5 yellows.<BR>\n" );
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document.write( "8 = k/(5)^2 <BR>\n" );
document.write( "k = 200<BR>\n" );
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document.write( "Equation for this relation is g = 200/y^2<BR>\n" );
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document.write( "How many would there be if there were 10 yellows? <BR>\n" );
document.write( "g = 200/(10)^2<BR>\n" );
document.write( "g = 200/100<BR>\n" );
document.write( "g = 2 green beans when there are 10 yellow<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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