document.write( "Question 1093375: The sum of the ages of A and B is 41 years now. 10 years ago, A was twice as old as B was then. Find their ages now. \n" ); document.write( "
Algebra.Com's Answer #708033 by ankor@dixie-net.com(22740)\"\" \"About 
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The sum of the ages of A and B is 41 years now.
\n" ); document.write( "a + b = 41
\n" ); document.write( "10 years ago, A was twice as old as B was then.
\n" ); document.write( "a-10 = 2(b-10)
\n" ); document.write( "a - 10 = 2b - 20
\n" ); document.write( "a = 2b - 20 + 10
\n" ); document.write( "a = 2b - 10
\n" ); document.write( " Find their ages now.
\n" ); document.write( "In the first equation, replace a with (2b-10)
\n" ); document.write( "2b - 10 + b = 41
\n" ); document.write( "3b = 41 + 10
\n" ); document.write( "3b = 51
\n" ); document.write( "b = 51/3
\n" ); document.write( "b = 17 yrs
\n" ); document.write( ":
\n" ); document.write( "Find a
\n" ); document.write( "a = 2(17) - 10
\n" ); document.write( "a = 34 - 10
\n" ); document.write( "a = 24 yrs \n" ); document.write( "
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