document.write( "Question 1093360: How do you find 3 consecutive numbers such that 3 times the 2nd number is 93 more than the largest number? \n" ); document.write( "

Algebra.Com's Answer #708008 by greenestamps(13200) $\"\"$ $\"About$

You can put this solution on YOUR website!

An even easier way to solve the problem is to note that the given information says nothing about the first of the three numbers. So really all you have is

\n" ); document.write( "\"3 times a number is 93 more than the next number\"

\n" ); document.write( " $\"3x+=+%28x%2B1%29%2B93\"$
\n" ); document.write( " $\"3x+=+x%2B94\"$
\n" ); document.write( " $\"2x+=+94\"$
\n" ); document.write( " $\"x+=+47\"$

\n" ); document.write( "Since we ignored the \"first number\" mentioned in the problem, our answer of 47 is the \"second\" number; so the three numbers are 46, 47, and 48. \n" ); document.write( "

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