document.write( "Question 1093348: could you please help me with this equation in interval notation
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document.write( "(x-9)(x+3)(x+6)>(or equal) 0\r
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document.write( "I tried and got [9,infinity) but I don't know if I am supposed to use the sign diagram where it would be positive inbetween (-6,-3) U (9,infinity) \n" );
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Algebra.Com's Answer #707990 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! (x-9)(x+3)(x+6)>(or equal) 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-9)(x+3)(x+6)>=0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Three critical x-values are -6, -3, and 9. \n" ); document.write( "The intervals on the real number line you want to check are (-infinity, -6], [-6, -3], [-3, 9], and [9, infinity). \n" ); document.write( "Check any value within each interval to find if that interval works or not works.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " (-infinity, -6] [-6, -3] [-3, 9] [9, infinity)\r\n" ); document.write( "signs (-)(-)(-) (-)(-)(+) (-)(+)(+) (+)(+)(+)\r\n" ); document.write( "result sign (-) (+) (-) (+)\r\n" ); document.write( " FALSE TRUE FALSE TRUE\r\n" ); document.write( " \n" ); document.write( "The solution set, of all the numbers that can make the equation true is \n" ); document.write( "[-6,-3] U [9, infinity).\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "NOTE: the form of the bracket for the interval notation, is important. Square bracket INCLUDES the boundary value. Curved bracket EXCLUDES the boundary value. \n" ); document.write( " |