document.write( "Question 1093360: How do you find 3 consecutive numbers such that 3 times the 2nd number is 93 more than the largest number? \n" ); document.write( "
Algebra.Com's Answer #707979 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "How do you find 3 consecutive numbers such that 3 times the 2nd number is 93 more than the largest number?
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The NON-CONFUSING method:
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document.write( "Let the 1st number be F
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document.write( "Then others are F + 1, and F + 2
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document.write( "We then get: 3(F + 1) = F + 2 + 93
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document.write( "3F + 3 = F + 95
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document.write( "3F - F = 95 - 3
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document.write( "2F = 92
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document.write( "F, or 1st number = \"highlight_green%28matrix%281%2C3%2C+92%2F2%2C+%22=%22%2C+46%29%29\"
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document.write( "Others: 
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document.write( "That's all....nothing CONFUSING or COMPLEX! \n" );
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