document.write( "Question 1093360: How do you find 3 consecutive numbers such that 3 times the 2nd number is 93 more than the largest number? \n" ); document.write( "
Algebra.Com's Answer #707977 by josgarithmetic(39620)\"\" \"About 
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\n" ); document.write( "How do you find 3 consecutive numbers such that 3 times the 2nd number is 93 more than the largest number?
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\n" ); document.write( "\n" ); document.write( "More than one way to do this, but give a variable to one of the consecutive numbers.\r
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\n" ); document.write( "\n" ); document.write( "n, first number
\n" ); document.write( "n+1 and n+2, the next two numbers\r
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\n" ); document.write( "\n" ); document.write( "Translate the description exactly as it was written:
\n" ); document.write( "\"3%28n%2B1%29=%28n%2B2%29%2B93\"
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\n" ); document.write( "\"3n%2B3=n%2B95\"
\n" ); document.write( "\"2n=92\"
\n" ); document.write( "\"n=46\"
\n" ); document.write( "---------------------\"n%2B2=highlight%2848%29\"\r
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\n" ); document.write( "\n" ); document.write( "BETTER WAY:
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\n" ); document.write( "Let n be the asked-for \"largest number\".
\n" ); document.write( "The numbers are therefore n-2, n-1, and n.
\n" ); document.write( "\"3%28n-1%29=n%2B93\"
\n" ); document.write( "\"3n-3=n%2B93\"
\n" ); document.write( "\"2n=96\"
\n" ); document.write( "\"highlight%28n=48%29\"-----\"largest number\"
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