document.write( "Question 1093247: Find the sample size, n, needed to estimate the percentage of adults who have consulted fortune tellers. Use a 0.01 margin of error, use a confidence level of 95% and use results from a prior poll suggesting that 16% of adults have consulted fortune tellers.\r
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document.write( "(Round up to the nearest integer.) \n" );
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Algebra.Com's Answer #707932 by Boreal(15235) You can put this solution on YOUR website! the half interval of a confidence interval is z*sqrt(p*(1-p))/n=0.01, the margin of error. \n" ); document.write( "substitute \n" ); document.write( "1.96*sqrt [(0.16*0.84)/n]=0.01 \n" ); document.write( "square both sides, multiply by n. \n" ); document.write( "3.84*0.16*0.84=0.0001n=0.5161 \n" ); document.write( "divide by 0.0001 \n" ); document.write( "n=5161 \n" ); document.write( " |