document.write( "Question 1093247: Find the sample​ size, n, needed to estimate the percentage of adults who have consulted fortune tellers. Use a 0.01 margin of​ error, use a confidence level of 95​% and use results from a prior poll suggesting that 16​% of adults have consulted fortune tellers.\r
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Algebra.Com's Answer #707932 by Boreal(15235)\"\" \"About 
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the half interval of a confidence interval is z*sqrt(p*(1-p))/n=0.01, the margin of error.
\n" ); document.write( "substitute
\n" ); document.write( "1.96*sqrt [(0.16*0.84)/n]=0.01
\n" ); document.write( "square both sides, multiply by n.
\n" ); document.write( "3.84*0.16*0.84=0.0001n=0.5161
\n" ); document.write( "divide by 0.0001
\n" ); document.write( "n=5161
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