document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1093283>Question 1093283</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Find the perimeter of a regular hexagon that is circumscribed by a circle with radius r = 11 m.<BR>\n" );
document.write( "Select one:<BR>\n" );
document.write( " a.<BR>\n" );
document.write( " 33 m<BR>\n" );
document.write( " b.<BR>\n" );
document.write( " 66 m<BR>\n" );
document.write( " c.<BR>\n" );
document.write( " 33&#8730;3 m<BR>\n" );
document.write( " d.<BR>\n" );
document.write( "  66&#8730;3 m\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #707923 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=707923\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The radius goes to the vertices of the hexagon.  This creates 6 isosceles triangles with sides 11, vertex angle (opposite the side of the hexagon) of 60 degrees. If this triangle is bisected, there are now 12 triangles with 30-60-90.  The short leg is half of one side of the hexagon, and half the hypotenuse of 11, so it is 5.5.  The pair of short legs are 11 cm, so the triangle is equilateral, and the circumference of the hexagon is 11*6=66 m<BR>\n" );
document.write( "B. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );