document.write( "Question 1093309: Katie invested a total of $6000 part at 2% simple interests and a part at 3% simple interest s. At the end of 1 year, the investments had earned $152 interest. How much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #707918 by Boreal(15235)\"\" \"About 
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x at 2%=.02x
\n" ); document.write( "6000-x at 3%=180-.03x
\n" ); document.write( "their sum, -.01x+180=152
\n" ); document.write( "-.01x=-28
\n" ); document.write( "x=$2800@2%=$56
\n" ); document.write( "6000-x=$3200@3%=$96
\n" ); document.write( "That sum is $152.
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