document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1093291>Question 1093291</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me to solve this problem-<BR>\n" );
document.write( "By what number should (-3/2)to the power-3 be divided so that the quotient may be(4/27)to the power-2?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #707901 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=707901\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> By what number should (-3/2)to the power-3 be divided so that the quotient may be(4/27)to the power-2?<BR>\n" );
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document.write( "(-3/2)^-3/n = (4/27)^-2<BR>\n" );
document.write( "n = (-3/2)^-3/(4/27)^-2<BR>\n" );
document.write( "Multiply NUM and DEN by (4/27)^2<BR>\n" );
document.write( "n = (-3/2)^-3*(4/27)^2/1<BR>\n" );
document.write( "Multiply NUM and DEN by (-3/2)^3<BR>\n" );
document.write( "n = (4/27)^2/(-3/2)^3<BR>\n" );
document.write( "n = (16/729)/(-27/8)<BR>\n" );
document.write( "Invert the divisor and mutliply<BR>\n" );
document.write( "n = (16/729)(-8/27)<BR>\n" );
document.write( "n = -128/19683<BR>\n" );
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