document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1093260>Question 1093260</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.) If 15 cm on a map represents 2.5 km of actual ground, how many centimetres would 15 km of actual ground be on the map?\r<BR>\n" );
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document.write( "2.) If the ratio of yellow pigment to blue pigment in a shade of green paint is 2:3, how many drops of yellow pigment will be needed of 12 drops of blue are used?\r<BR>\n" );
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document.write( "3.) If this treatment costs the consumer $68.00 and the cost of labour and materials used is $14.20, what is the ratio of consumer price to actual cost?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #707888 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=707888\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> problem 1:\r<BR>\n" );
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document.write( "If 15 cm on a map represents 2.5 km of actual ground, how many centimetres would 15 km of actual ground be on the map? \r<BR>\n" );
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document.write( "15 cm on the map equals 2.5 km on the ground.\r<BR>\n" );
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document.write( "the ratio of m/g = 15 / 2.5\r<BR>\n" );
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document.write( "when g = 15 km, you want to find m.\r<BR>\n" );
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document.write( "your equation is 15 / 2.5 = x / 15\r<BR>\n" );
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document.write( "cross multiply to get 15 * 15 = 2.5 * x\r<BR>\n" );
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document.write( "divide both sides of this equation by 2.5 and solve for x to get:\r<BR>\n" );
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document.write( "x = 15 * 15 / 2.5 = 90\r<BR>\n" );
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document.write( "you can also do the following.\r<BR>\n" );
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document.write( "ratio of map to ground is 15 / 2.5\r<BR>\n" );
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document.write( "divide 15 by 2.5 to get m/g = 6\r<BR>\n" );
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document.write( "you get 6 cm on the map for every km on the ground.\r<BR>\n" );
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document.write( "15 km on the ground is therefore equal to 15 * 6 = 90 cm on the map.\r<BR>\n" );
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document.write( "problem 2:\r<BR>\n" );
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document.write( " If the ratio of yellow pigment to blue pigment in a shade of green paint is 2:3, how many drops of yellow pigment will be needed of 12 drops of blue are used? \r<BR>\n" );
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document.write( "y = yellow<BR>\n" );
document.write( "b = blue\r<BR>\n" );
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document.write( "y/b = 2/3 for a particular shade of green.\r<BR>\n" );
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document.write( "if 12 drops of blue, how many yellow are needed?\r<BR>\n" );
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document.write( "y/b = 2/3 = x/12\r<BR>\n" );
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document.write( "cross multiply to get 2*12 = 3*x\r<BR>\n" );
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document.write( "divide both sides of the equation by 3 and solve for x to get:\r<BR>\n" );
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document.write( "x = 2*12/3 = 2*4 = 8\r<BR>\n" );
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document.write( "you will need 8 drops of yellow if you have 12 drops of blue.\r<BR>\n" );
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document.write( "also you can do:\r<BR>\n" );
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document.write( "y/b = 2/3\r<BR>\n" );
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document.write( "solve for y to get y = 2/3 * b\r<BR>\n" );
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document.write( "when b = 12, then y = 2/3 * 12 = 2 * 4 = 8\r<BR>\n" );
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document.write( "problem 3:\r<BR>\n" );
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document.write( "If this treatment costs the consumer $68.00 and the cost of lab0r and materials used is $14.20, what is the ratio of consumer price to actual cost?\r<BR>\n" );
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document.write( "r = revenue equals consumer price = cost to the consumer<BR>\n" );
document.write( "c = actual cost equals cost of labor and materials.\r<BR>\n" );
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document.write( "ratio of consumer price to actual cost would then be r/c\r<BR>\n" );
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document.write( "r = 68<BR>\n" );
document.write( "c = 14.2\r<BR>\n" );
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document.write( "r/c = 68/14.2\r<BR>\n" );
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document.write( "that's the ratio.\r<BR>\n" );
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document.write( "solve for r to get r = 68/14.2 * c = 4.788732394 * c\r<BR>\n" );
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document.write( "solve for c to get c = r / (68/14.2) which becomes c = r * (14.2/68) which becomes c = .2088234294 * r\r<BR>\n" );
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document.write( "so, when r = 68, then c = .2088234294 * 68 = 14.2 and when c = 14.2, r = 4.788732394 * 14.2 = 68.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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