document.write( "Question 1093273: Please show me how to solve for x here:
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Algebra.Com's Answer #707887 by Edwin McCravy(20055)\"\" \"About 
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You must write 7^(x+2)=343, enclosing the exponent in parentheses.\r\n" );
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document.write( "\"7%5E%28x%2B2%29=343\"\r\n" );
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document.write( "We must break down the number 343.  We try dividing it by 3, but it\r\n" );
document.write( "gives 114.333... (no good!)  We know it cannot be divisible by 5 \r\n" );
document.write( "because it does not end in 0 or 5. So we divide it by 7, and get\r\n" );
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document.write( "343 = 7*49 = 7*7*7 = 73 \r\n" );
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document.write( "Then we write 343 as 73\r\n" );
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document.write( "\"7%5E%28x%2B2%29=7%5E3\"\r\n" );
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document.write( "And we use the principle that says if the bases of the exponentials\r\n" );
document.write( "are the same on both sides, and that base is positive but not\r\n" );
document.write( "equal to 1, then we may set the exponents equal and drop the base:\r\n" );
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document.write( "\"x%2B2=3\"\r\n" );
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document.write( "\"x=1\"\r\n" );
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document.write( "Edwin
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