document.write( "Question 1093239: please help me solve this question
\n" ); document.write( "it is supposed to be represented in interval notion
\n" ); document.write( "x^2<4x+12
\n" ); document.write( " I tried moving everything to the left and then factorized and I received (x-6) (x+2)<0 and as an answer In interval notion I wrote (-2,6) u (6,infinity)
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Algebra.Com's Answer #707858 by josgarithmetic(39625)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2%3C4x%2B12\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-4x-12%3C0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-6%29%28x%2B2%29%3C0\", which tells you the left side must be LESS THAN 0.
\n" ); document.write( "The ROOTS for the expression on left are -2 and +6.
\n" ); document.write( "The expression will be LESS THAN 0 for x between -2 and +6, excluding them. (Check that for yourself).\r
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\n" ); document.write( "\n" ); document.write( "\"-2%3Cx%3C6\"
\n" ); document.write( "OR
\n" ); document.write( "(-2, 6), in interval notation
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