document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1093214>Question 1093214</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two trains, one traveling twice the speed of the other, start st the same time from stations which are 306km apart and travel towards each other. In 3 hours, the trains pass each other. Frind the rate of each train  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #707821 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13208)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=707821\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br>Another nice algebraic solution from Boreal...<br><BR>\n" );
document.write( "But let's see if a more informal solution makes sense to you.<br><BR>\n" );
document.write( "The stations are 306km apart; one train travels twice as fast as the other.  That means that, at the time the trains pass each other, the faster train has covered 2/3 of the distance and the slower train has covered 1/3 of the distance.<br><BR>\n" );
document.write( "2/3 of the 306km for the faster train is 204km; since both trains traveled for 3 hours before they passed each other, the speed of the faster train is 204/3 = 68km/hr. And then the speed of the slower train is half of that, or 34km/hr. </SPAN>\n" );
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