document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1093214>Question 1093214</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two trains, one traveling twice the speed of the other, start st the same time from stations which are 306km apart and travel towards each other. In 3 hours, the trains pass each other. Frind the rate of each train  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #707818 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=707818\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> slower train at x kph<BR>\n" );
document.write( "faster at 2x kph<BR>\n" );
document.write( "total closing speed is their sum or 3x kph<BR>\n" );
document.write( "in 3 hours, they pass so 3x kph* 3h units are km=9x km=306 km<BR>\n" );
document.write( "x km=34 km<BR>\n" );
document.write( "2x=68 km<BR>\n" );
document.write( "In 3 hours the slower train travels 102 km and the faster 204 km.<BR>\n" );
document.write( "the slower train travels at 34 kph and the faster at 68 kph. </SPAN>\n" );
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