document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1093187>Question 1093187</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Problem 2:  Given ABCD is a parallelogram, what value must x & y have?\r<BR>\n" );
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document.write( "(picture of the problem) https://imgur.com/Zr7GLjL </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #707799 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=707799\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The long way:<BR>\n" );
document.write( "5y-28=3y+12, since they are congruent.<BR>\n" );
document.write( "2y=40<BR>\n" );
document.write( "y=20 degrees<BR>\n" );
document.write( "check that 72=72<BR>\n" );
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document.write( "4x-12+5y-28=180, since same side angles are supplementary. I could use 3y+12, because that is equal<BR>\n" );
document.write( "substitute 100 for 5y<BR>\n" );
document.write( "4x+100-40=180<BR>\n" );
document.write( "4x=120<BR>\n" );
document.write( "x=30 degrees<BR>\n" );
document.write( "4x-12=108 degrees<BR>\n" );
document.write( "108+72=180 degrees.<BR>\n" );
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document.write( "The short way: Opposite angles are congruent, so 4x-12=108 and that can give x directly. </SPAN>\n" );
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