document.write( "Question 1093171: Kellen's boat travels 20 mph. Find the rate of the river current if she can travel 6 mi upstream in the same amount of time she can go 10 mi downstream. (Let x=the rate of the current.) The rate of the river current is what? \n" ); document.write( "
Algebra.Com's Answer #707787 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! If x is the rate of the current, then: \n" ); document.write( "6/20-x=10/20+x (being inversely proportional) \n" ); document.write( "200-10x=120+6x \n" ); document.write( "80=16x \n" ); document.write( "x=5 \n" ); document.write( "The current is 5 mph. ☺☺☺☺ \n" ); document.write( " |