document.write( "Question 97226: This problem was similar to the other one I asked about. Perpendicular to the line y=2x-3;containing the point (1,-2) My answer was y=-1/2x and 1 1/2. My teacher remarked \"use improper fractions\" He wanted this graphed and two x y charts, mine were definitely wrong. \n" ); document.write( "
Algebra.Com's Answer #70777 by edjones(8007)\"\" \"About 
You can put this solution on YOUR website!
y=mx+b m=slope
\n" ); document.write( "y=2x-3 m=2 b=-3
\n" ); document.write( "a line perpendicular to any line has slope of -1/m. Since m=2 then -1/m=-1/2=-.5
\n" ); document.write( "y-y[1]=m(x-x[1]) point slope form.
\n" ); document.write( "For the perpendicular line: y-(-2)=-.5(x-1)) \"containing the point (1,-2)\"
\n" ); document.write( "y+2=-.5(x-1)
\n" ); document.write( "y+2=-.5x+.5
\n" ); document.write( "subtract 2 from both sides. y=-.5x-1.5
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\n" ); document.write( "\"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C2x-3%2C-.5x-1.5%29\"
\n" ); document.write( "Ed
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