document.write( "Question 97226: This problem was similar to the other one I asked about. Perpendicular to the line y=2x-3;containing the point (1,-2) My answer was y=-1/2x and 1 1/2. My teacher remarked \"use improper fractions\" He wanted this graphed and two x y charts, mine were definitely wrong. \n" ); document.write( "
| Algebra.Com's Answer #70777 by edjones(8007)     You can put this solution on YOUR website! y=mx+b m=slope \n" ); document.write( "y=2x-3 m=2 b=-3 \n" ); document.write( "a line perpendicular to any line has slope of -1/m. Since m=2 then -1/m=-1/2=-.5 \n" ); document.write( "y-y[1]=m(x-x[1]) point slope form. \n" ); document.write( "For the perpendicular line: y-(-2)=-.5(x-1)) \"containing the point (1,-2)\" \n" ); document.write( "y+2=-.5(x-1) \n" ); document.write( "y+2=-.5x+.5 \n" ); document.write( "subtract 2 from both sides. y=-.5x-1.5 \n" ); document.write( "Ed \n" ); document.write( " \n" ); document.write( "Ed \n" ); document.write( " \n" ); document.write( " |