document.write( "Question 1093099: HAROLD INVESTED $8000 FOR ONE YEAR, PART AT 11% SIMPLE INTREST AND PART AT 10% INTREST. IF HE EARNED A TOTAL OF $850 IN INTREST AT EACH RATE?\r
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document.write( "FOR 11% I GOT 5000
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document.write( "FOR 10% I GOT 3000\r
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document.write( "IS THIS Correct?
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Algebra.Com's Answer #707692 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x at 11% \n" ); document.write( "8000-x at 10% \n" ); document.write( ".11x+.10(8000-x)=850 \n" ); document.write( ".11x+800-.10x=850 \n" ); document.write( ".01x=50 \n" ); document.write( "x=$5000 \n" ); document.write( "8000-x=$3000 \n" ); document.write( "yes, you are correct. \n" ); document.write( " |