document.write( "Question 1093099: HAROLD INVESTED $8000 FOR ONE YEAR, PART AT 11% SIMPLE INTREST AND PART AT 10% INTREST. IF HE EARNED A TOTAL OF $850 IN INTREST AT EACH RATE?\r
\n" ); document.write( "\n" ); document.write( "FOR 11% I GOT 5000
\n" ); document.write( "FOR 10% I GOT 3000\r
\n" ); document.write( "\n" ); document.write( "IS THIS Correct?
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Algebra.Com's Answer #707692 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
x at 11%
\n" ); document.write( "8000-x at 10%
\n" ); document.write( ".11x+.10(8000-x)=850
\n" ); document.write( ".11x+800-.10x=850
\n" ); document.write( ".01x=50
\n" ); document.write( "x=$5000
\n" ); document.write( "8000-x=$3000
\n" ); document.write( "yes, you are correct.
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