document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1093092>Question 1093092</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The size of a Quantity Qi at time t is given by Q(t)=1300e^2.1t, Where t is measured in seconds.\r<BR>\n" );
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document.write( "a) Is the quantity Q increasing or decreasing with time?\r<BR>\n" );
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document.write( "b)what the initial value of Q?\r<BR>\n" );
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document.write( "c) What is the value of Q after 1.5 seconds?\r<BR>\n" );
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document.write( "d)In how many seconds (measured from t=0)will the quantity be equal to 2000? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #707685 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=707685\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> as t increases, e^2.1t is increasing, since it is positive.<BR>\n" );
document.write( "initial value is when t=0.  Then Q(t)=1300*e^0=1300.<BR>\n" );
document.write( "after 1.5 seconds, Q(t)=1300e^3.15=30336.88.<BR>\n" );
document.write( "2000=1300e^2.1t<BR>\n" );
document.write( "1.538=e^2.1t<BR>\n" );
document.write( "ln both sides<BR>\n" );
document.write( "0.4307=2.1 t.<BR>\n" );
document.write( "without rounding divide by 2.1<BR>\n" );
document.write( "t=0.2051<BR>\n" );
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