document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1093091>Question 1093091</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 44^(2x-9 )+23=55\r<BR>\n" );
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document.write( "Could you solve please. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #707684 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=707684\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 44^(2x-9 )+23=55<BR>\n" );
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document.write( "Subtract 23<BR>\n" );
document.write( "44^(2x-9) = 32<BR>\n" );
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document.write( "(2x-9)*log(44) = log(32)<BR>\n" );
document.write( "Can you do the rest?<BR>\n" );
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document.write( "2x-9 = log(32)/log(44)<BR>\n" );
document.write( "2x = 9 + log(32)/log(44)<BR>\n" );
document.write( "x = 9/2 + log(32)/(2log(44))\r<BR>\n" );
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document.write( " </SPAN>\n" );
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