document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1093090>Question 1093090</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (picture of the problem) https://imgur.com/pci4KhW\r<BR>\n" );
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document.write( "Complete the list of missing values below, Given: AB is congruent to BF, CB is congruent to CF, triangle DEF is equilateral, and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m%3CBFD ALIGN=MIDDLE  ALT=\"m%3CBFD\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 40deg.\r<BR>\n" );
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document.write( "(same as first link but only the triangle) https://imgur.com/4b3QvKW\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m%3C+DFE+=++_____o+ ALIGN=MIDDLE  ALT=\"m%3C+DFE+=++_____o+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m%3C+BFA+=++_____o ALIGN=MIDDLE  ALT=\"m%3C+BFA+=++_____o\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m%3C+ABF+=++_____o ALIGN=MIDDLE  ALT=\"m%3C+ABF+=++_____o\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #707682 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=707682\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If E is the unnamed vertex at the right, then DFE is 60 degrees, because it is an equilateral triangle.<BR>\n" );
document.write( "DFE and BFD together are 100 degrees, 60+40, and therefore BFA is 80 degrees.  That makes ABF 20 degrees, because the two angles of an isosceles triangle that are equal comprise 160 degrees. </SPAN>\n" );
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