document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1092978>Question 1092978</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve -25^-3/2 ? I also need to solve 3/3 multiply by 4/2 using the following principal root product rule quotient rule reciprocal nth root? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #707590 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=707590\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'll help you with the first one<BR>\n" );
document.write( "-25^(-3/2)<BR>\n" );
document.write( "rewrite as follows:<BR>\n" );
document.write( "(-1)/(25^(3/2))<BR>\n" );
document.write( "Let's separate the exponent of 25^(-3/2) into integer and fractional parts, like this 25^(-3/2) = 25^(1/2 - (4)/2) = 25^(-4/2)×sqrt(25):<BR>\n" );
document.write( "-25^(-4/2)sqrt(25)<BR>\n" );
document.write( "= -25^(-2)sqrt(25)<BR>\n" );
document.write( "Evaluate 25^2.<BR>\n" );
document.write( " | 2 | 5<BR>\n" );
document.write( "× | 2 | 5<BR>\n" );
document.write( "1 | 2 | 5<BR>\n" );
document.write( "5 | 0 | 0<BR>\n" );
document.write( "6 | 2 | 5:<BR>\n" );
document.write( "-(sqrt(25))/(625)<BR>\n" );
document.write( "Let's simplify, like this sqrt(25) = sqrt(5^2) = 5:<BR>\n" );
document.write( "-5/625<BR>\n" );
document.write( "Divide both numbers by 5 to get your answer:<BR>\n" );
document.write( "(-1)/125 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );