document.write( "Question 1092943: Use the properties of exponents to simplify the expression. \r
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\n" ); document.write( "\n" ); document.write( "If would be great if you could please explain why the answer is 1/5.
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Algebra.Com's Answer #707566 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
5^2 * 5^-3 = 5^2 / 5^3 = 5^(2-3) = 5^-1 = 1/5^1 = 1/5\r
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\n" ); document.write( "\n" ); document.write( "this has to do with properties of exponents.\r
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\n" ); document.write( "\n" ); document.write( "the rule is:\r
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\n" ); document.write( "\n" ); document.write( "x^(-a) is equal to 1 / x^a\r
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\n" ); document.write( "\n" ); document.write( "x^a is equal to 1 / x^(-a)\r
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\n" ); document.write( "\n" ); document.write( "therefore:\r
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\n" ); document.write( "\n" ); document.write( "5^2 * 5^(-3) is equal to 5^2 * 1 / 5^3 which is equal to 5^2 / 5^3.\r
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\n" ); document.write( "\n" ); document.write( "another rule is:\r
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\n" ); document.write( "\n" ); document.write( "x^a / x^b = x^(a-b)\r
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\n" ); document.write( "\n" ); document.write( "therefore:\r
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\n" ); document.write( "\n" ); document.write( "5^2 / 5^3 is equal to 5^(2-3) which is equal to 5^(-1) which is equal to 1/5.\r
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\n" ); document.write( "\n" ); document.write( "here's some good references on exponent arithmetic.\r
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\n" ); document.write( "\n" ); document.write( "http://www.wtamu.edu/academic/anns/mps/math/mathlab/beg_algebra/beg_alg_tut26_exp.htm\r
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\n" ); document.write( "\n" ); document.write( "http://www.wtamu.edu/academic/anns/mps/math/mathlab/beg_algebra/beg_alg_tut29_negexp.htm\r
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\n" ); document.write( "\n" ); document.write( "http://www.wtamu.edu/academic/anns/mps/math/mathlab/int_algebra/int_alg_tut23_exppart1.htm\r
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\n" ); document.write( "\n" ); document.write( "in fact, this website has many tutorials that are hugely helpful as tutorials and as references.\r
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\n" ); document.write( "\n" ); document.write( "here's the main website.\r
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\n" ); document.write( "\n" ); document.write( "http://www.wtamu.edu/academic/anns/mps/math/mathlab/int_algebra/index.htm\r
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\n" ); document.write( "\n" ); document.write( "on the questions of negative exponents, here's some more useful information.\r
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\n" ); document.write( "\n" ); document.write( "if the negative exponents is in the numerator, then place it in the denominator and make the exponent positive.\r
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\n" ); document.write( "\n" ); document.write( "if the negative expnent is in the denominator, then place it in the numerator and make the exponent positive.\r
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\n" ); document.write( "\n" ); document.write( "example:\r
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\n" ); document.write( "\n" ); document.write( "5^(-3) / 5^(-5) = 5^5 / 5^3 = 5^(5-3) = 25\r
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\n" ); document.write( "\n" ); document.write( "this could also have been solved without doing that because:\r
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\n" ); document.write( "\n" ); document.write( "5^(-3) / 5^(-5) = 5^(-3 - (-5)) = 5^(-3 + 5) = 5^2 = 25\r
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\n" ); document.write( "\n" ); document.write( "note that numerator and denominator are always there but implied because:\r
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\n" ); document.write( "\n" ); document.write( "any number by itself has a denominator of 1 and is also multiplied by 1.\r
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\n" ); document.write( "\n" ); document.write( "therefore 5^(-3) = (1 * 5^(-3)) / 1.\r
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\n" ); document.write( "\n" ); document.write( "place it in the denominator and make the exponent positive and you have 1 / (5^3 * 1) which simplifies to 1 / 5^3.\r
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\n" ); document.write( "\n" ); document.write( "practice a few and you should have it in reasonably short period of time.\r
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\n" ); document.write( "\n" ); document.write( "don't foget to study the references and to do the sample questions as well.\r
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\n" ); document.write( "\n" ); document.write( "this allows you to solidify your learning.\r
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\n" ); document.write( "\n" ); document.write( "here's 1 last example:\r
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\n" ); document.write( "\n" ); document.write( "25x^-3 is equal to 25/x^3.\r
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\n" ); document.write( "\n" ); document.write( "the 25 stays on top because it has a positive exponent which is 1, since any number raised to the power of 1 is that same number.\r
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\n" ); document.write( "\n" ); document.write( "the x^-3 goes to the denominator and the exponent is made positive.\r
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\n" ); document.write( "\n" ); document.write( "note that the rationale for moving it to the denominator is as follows:\r
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\n" ); document.write( "\n" ); document.write( "25 * x^3 is equal to 25 * 1 / x^3 which is equal to (25 * 1) / x^3 which is equal to 25 / x^3\r
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\n" ); document.write( "\n" ); document.write( "likewise x^-3 / y^-3 is equal to (1/x^3) / (1/y^3) which is equal to (1/x^3) * (y^3/1) which is equal to (1 * y^3) / (x^3 * 1) which is equal to y^3 / x^3.\r
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\n" ); document.write( "\n" ); document.write( "send me an email if you have any further questions on this\r
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