document.write( "Question 1092935: A supermarket is selling 2 types of candies, orange slices and strawberry leaves. The orange slices cost $1.27 per pound and the strawberry leaves cost $1.77 per pound. How many pounds of each should be mixed to get a 13-pound mixture that sells for $19.01?
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Algebra.Com's Answer #707551 by josgarithmetic(39617) $\"\"$ $\"About$

You can put this solution on YOUR website!
x for the cheaper $1.27 per pound candy
\n" ); document.write( "y for the $1.77 per pound candy\r
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\n" ); document.write( "\n" ); document.write( "Account for the mixture mass:
\n" ); document.write( " $\"x%2By=13\"$ \r
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\n" ); document.write( "\n" ); document.write( "Account for the mixture COST:
\n" ); document.write( " $\"1.27x%2B1.77y=19.0\"$ \r
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\n" ); document.write( "\n" ); document.write( "More than one way to go from there. One of them is like this:
\n" ); document.write( " $\"y=13-x\"$
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\n" ); document.write( " $\"1.27x%2B1.77%2813-x%29=19\"$
\n" ); document.write( " $\"1.27x%2B23.01-1.77x=19\"$
\n" ); document.write( " $\"-0.5x=19-23.01\"$
\n" ); document.write( " $\"x=2%2823.01-19%29\"$
\n" ); document.write( " $\"x=8.02\"$ , $\"y=4.98\"$ \r
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\n" ); document.write( "\n" ); document.write( "(NOTE: Misread problem; not saw the wrapped \"1\" at the end, on the page for the $19.01) \n" ); document.write( "

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