document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1092898>Question 1092898</A>: <I><SPAN STYLE=\"word-break: break-all;\"> As a condition of employment, Fashion Industries applicants must pass a drug test. Of the last 225 applicants, 20 failed the test. (Use  z Distribution Table.)<BR>\n" );
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document.write( "a.	<BR>\n" );
document.write( "Develop a 95% confidence interval for the proportion of applicants that fail the test. (Round your answers to 3 decimal places.)<BR>\n" );
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document.write( "  For the applicants the confidence interval is between ____ and ____.<BR>\n" );
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document.write( "b.	Would it be reasonable to conclude that more than 8% of the applicants fail the test?<BR>\n" );
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document.write( "	Yes<BR>\n" );
document.write( "	No<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #707507 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=707507\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p hat is 20/225=0.089<BR>\n" );
document.write( "95% CI is phat +/- 1.96* sqrt(p*(1-p))/n<BR>\n" );
document.write( "half interval is 1.96+/- sqrt (0.089*0.911)/225); sqrt term = 0.0190, and product is 0.037<BR>\n" );
document.write( "interval is (0.052, 0.126)<BR>\n" );
document.write( "No, since every value in the interval is possible one may say that values below 5.2% would not be consistent nor values above 12.7%.  But the values between 5.2 and 8% are entirely feasible.<BR>\n" );
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