document.write( "Question 14061: The sum of three numbers is 6. The
\n" ); document.write( "third number is the sum of the first
\n" ); document.write( "and second number. The first number
\n" ); document.write( "is one more than the third number.
\n" ); document.write( "Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #7075 by bam878s(77)\"\" \"About 
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let x = third number
\n" ); document.write( " y = first number
\n" ); document.write( " z = second number
\n" ); document.write( "We know x+y+z=6
\n" ); document.write( "also x = y+z (1).
\n" ); document.write( "and y = x+1 (2).
\n" ); document.write( "plug y back into equation (1) to get x = (x+1) + z.
\n" ); document.write( "Now subtract x from both sides of this equation to get
\n" ); document.write( "0=1+z.
\n" ); document.write( "Now subtract 1 from both sides to get
\n" ); document.write( "-1=z.
\n" ); document.write( "Now we know x=y+(-1), x+y+(-1)=6.
\n" ); document.write( "plug x into this equation to get
\n" ); document.write( "(y+(-1)) + y + (-1) = 6
\n" ); document.write( "solve for y.
\n" ); document.write( "we have,
\n" ); document.write( "y-1+y-1=6
\n" ); document.write( "2y-2=6
\n" ); document.write( "add 2 to both sides to get
\n" ); document.write( "2y=8
\n" ); document.write( "now divide by 2 to get
\n" ); document.write( "y=4\r
\n" ); document.write( "\n" ); document.write( "Now that we know z and y we can use equation (1) to find x.
\n" ); document.write( "x=4+(-1)= 3.\r
\n" ); document.write( "\n" ); document.write( "Hope this helps \n" ); document.write( "
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