document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1092725>Question 1092725</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Divide and express the answer in simplest form:\r<BR>\n" );
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document.write( "&#8730; 3/3 - 1 / &#8730; 3/3 +1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #707421 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=707421\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> &#8730; 3/3 - 1 / &#8730; 3/3 +1<BR>\n" );
document.write( "put over 3 numerator and denominator<BR>\n" );
document.write( "(sqrt(3)-3/3 divided by sqrt(3)+3/3<BR>\n" );
document.write( "the 3 denominator cancels out<BR>\n" );
document.write( "sqrt(3)-3/sqrt3)+3.  Multiply top and bottom by conjugate sqrt(3)-3<BR>\n" );
document.write( "this is [sqrt(3)-3)}^2/-6, the -6 comes from 3-9<BR>\n" );
document.write( "this can be written as 3-2*(3)sqrt(3)+9/-6<BR>\n" );
document.write( "or 12-6 sqrt(3)/-6=<BR>\n" );
document.write( "sqrt(3)-2 </SPAN>\n" );
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