document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=97015>Question 97015</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A metal alloy that is 17% copper to make jewelry. How many ounces of a 14% alloy must be mixed with a 23% alloy to form 72 ounces of the desired alloy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #70738 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=70738\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .17*72=.23x+.14(72-x)<BR>\n" );
document.write( "12.24=.23x+10.08-.14x<BR>\n" );
document.write( "12.24=.09x+10.08<BR>\n" );
document.write( ".09x=12.24-10.08<BR>\n" );
document.write( ".09x=2.16<BR>\n" );
document.write( "x=2.16/.09<BR>\n" );
document.write( "x=24 ounces of 23% alloy is needed.<BR>\n" );
document.write( "72-24=48 ounces of 14% is also needed.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "12.24=.23*24+.14*48<BR>\n" );
document.write( "12.24=5.52+6.72<BR>\n" );
document.write( "12.24=12.24<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );