document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1092736>Question 1092736</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A researcher is investigating a specimen of bacteria. She finds that the original <BR>\n" );
document.write( "1000 bacteria grew to 2,048,000 in 60 hours. How fast does the bacteria (a) <BR>\n" );
document.write( "double? (b) quadruple? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #707342 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=707342\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> N(t) = No * e^(r * t), where N(t) is population after time t, No is original population, r is growth rate, t is time<BR>\n" );
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document.write( "take natural log of both sides of =<BR>\n" );
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document.write( "ln(N/No) = r * t<BR>\n" );
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document.write( "r = ln(N/No) / t = ln(2,048,000/1000) / 60 = 0.1271<BR>\n" );
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document.write( "t = ln(N/No) / r<BR>\n" );
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document.write( "a) t = ln(2000/1000) /  0.1271 = 5.4536 hours<BR>\n" );
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document.write( "b) t = ln(4000/1000) /  0.1271 = 10.9071 hours<BR>\n" );
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