document.write( "Question 567885: a father is twice older than his son and the sum of their ages is 48.How old is each? \n" ); document.write( "
Algebra.Com's Answer #707335 by ikleyn(52790)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "Let the son's age is x years.\r\n" ); document.write( "\r\n" ); document.write( "Then the father's age is 3x years, (twice older means \"three times old as\") and the condition says that\r\n" ); document.write( "\r\n" ); document.write( "x + 3x = 48.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Hence, 4x = 48 and x =\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |