document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=567885>Question 567885</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a father is twice older than his son and the sum of their ages is 48.How old is each? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #707322 by </B><A HREF=/tutors/aboutme.mpl?userid=Gurajan><B>Gurajan(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gurajan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=707322\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let age of son be x years. <BR>\n" );
document.write( "Age of father's be y years<BR>\n" );
document.write( "Now according to ques.<BR>\n" );
document.write( "  x+y=48<BR>\n" );
document.write( "  Y=2x<BR>\n" );
document.write( "So eq.becomes,<BR>\n" );
document.write( " x+y=48<BR>\n" );
document.write( "2x-y=0<BR>\n" );
document.write( "Adding these eq.<BR>\n" );
document.write( "3x=48<BR>\n" );
document.write( "x=16<BR>\n" );
document.write( "y=2x =2×16=32<BR>\n" );
document.write( "Age of son is 16<BR>\n" );
document.write( "Age of father is 32.<BR>\n" );
document.write( "Ik                    </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );