document.write( "Question 1092388: MO bisects < LMN, m < LMO = 6x - 27 and m < NMO = 2x+33 solve for X and find m < LMN \n" ); document.write( "
Algebra.Com's Answer #707296 by josgarithmetic(39632)\"\" \"About 
You can put this solution on YOUR website!
Angles LMO and NMO are congruent, of equal measures, so \"6x-27=2x%2B33\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4x=33%2B27\"\r
\n" ); document.write( "\n" ); document.write( "\"4x=60\"\r
\n" ); document.write( "\n" ); document.write( "\"x=15\"\r
\n" ); document.write( "\n" ); document.write( ".\r
\n" ); document.write( "\n" ); document.write( ".
\n" ); document.write( "
\n" );