document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=97151>Question 97151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find two consecutive odd integers such that 3 times the first integer<BR>\n" );
document.write( "is 5 more than twice the second.  Please help me figure this one out. <BR>\n" );
document.write( "I also would like to no if there is a way that I can check to see if the question I am about to ask is not already been answered somewhere? Can I search the web site some how? Could you tell me how if it is possible?<BR>\n" );
document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #70728 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=70728\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1) Let x be the first odd integer, then x+2 will be the next consecutive odd integer.<BR>\n" );
document.write( "From the problem description, you can write:<BR>\n" );
document.write( "3x = 2(x+2)+5 Apply the distributive property to the right side.<BR>\n" );
document.write( "3x = 2x+4+5  Simplify.<BR>\n" );
document.write( "3x = 2x+9 Subtract 2x from both sides.<BR>\n" );
document.write( "x = 9<BR>\n" );
document.write( "The two integers are 9 and 11\r<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "3(9) = 2(11)+5<BR>\n" );
document.write( "27 = 22+5<BR>\n" );
document.write( "27 = 27\r<BR>\n" );
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document.write( "2)  I don't know of an easy way to see if a similar problem to one you want help with has already been answered.  You could try clicking on \"Recent problems solved by all\" and do a manual search but that could be quite time-consuming.  </SPAN>\n" );
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